IPL 2020: Play-offs explained

The Indian Premier (IPL) 2020 kicked off on 19th September in Dubai. The tournament witnessed a delayed start and outside India owing to the global pandemic COVID-19. BCCI’s luminous event didn’t fail to put up a stellar show despite the tight Coronavirus regulations.

Eventuating across three stadiums Dubai, Abu Dhabi, and Sharjah, the invigorating tournament churned out some nail biters as well as dominating performances. After the league stage, it is time for the playoffs. Here’s how it is going to transpire.

The top two teams based on points after 14 league games, that are Mumbai Indians and Delhi Capitals will face off in Qualifier 1 for the final. The winner of this game will directly qualify for the final. The teams in the 3rd (Sunrisers Hyderabad) and the 4th position (Royal Challengers Bangalore) will play an Eliminator where the campaign will conclude for the losing side. The winner of the Eliminator goes on to face the loser of Qualifier 1 in Qualifier 2. The winner climbs to cement a spot in the final and the loser bids adieu.

After an exciting run for the playoffs berth, Mumbai Indians were the only side who romped into the playoffs with 18 points from 14 games. Delhi Capitals emerged victorious in their concluding league stage game against Virat Kohli’s Royal Challengers Bangalore to secure the 2nd spot with 16 points. With Sunrisers Hyderabad thrashing Mumbai in their final game, RCB were pushed down to the fourth and the final spot for the playoffs. SRH’s win anchored them to the 3rd spot due to a superior net run rate.

Teams qualified for the Playoffs: 4

Mumbai Indians, Delhi Capitals, Sunrisers Hyderabad, and Royal Challengers Bangalore are the teams who have secured a playoff berth. While DC will face MI in Qualifier 1 on November 5 (Thursday), RCB will face Sunrisers Hyderabad in the Eliminator on November 6 (Friday).